3) Two numbers are in the ratio 2 : 3 and their HCF is 13. Find the LCM of those two numbers.
4) The LCM of two co-prime numbers is 5005. If one of the numbers is 65, then find the other number.
5) If the product of two co-prime numbers is 117, find the LCM of the numbers.
6) The product of HCF and LCM of two positive numbers is 24 and the difference between them is 2. Find the numbers.
Let x be the other number.
Product of the two numbers = LCM x HCF
Divide each side by 108.
x = (432 x 36) / 108
The other number is 144.
LCM x HCF = Product of the two numbers
Divide each side by 6.
Because the two numbers are in the ratio 2 : 3, the numbers can be assumed as 2x and 3x.
But, it is given that the HCF is 13.
Substitute x = 13 in 2x and 3x.
So, the two numbers are 26 and 36.
HCF x LCM = Product of the two numbers
13 x LCM = 26 x 39
Divide each side by 13.
LCM = (26 x 39) / 13
Let x be the other number.
Product of the two numbers = LCM x HCF
As the HCF of co-primes is 1,
Divide each side by 65.
The other number is 77.
Because the two numbers are co-prime, their HCF is 1.
LCM x HCF = Product of the two numbers
Because the difference between the two numbers is 2, the numbers can be assumed as x and (x + 2).
Product of the two numbers = LCM x HCF
Subtract 24 from each side.
Solve for x by factoring.
x 2 - 4x + 6x - 24 = 0
x(x - 4) + 6(x - 4) = 0
Because the numbers are positive x ≠ 6.
The other number :
So, the two numbers are 4 and 6.
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